Math, asked by khanshahabkhan203, 4 months ago

p³ + q³+ r ³ + 3 pqr​

Answers

Answered by chitrashri77
1

Answer:

p³+q³+r³-3pqr

=(p+q+r)(p²+q²+r²-(pq+qr+rp)

=(p+q+r){(p+q+r)²-3(pq+qr+rp)}

Answered by ItzBeautyBabe
1

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 {p}^{3}  +  {q}^{3}  +  {r}^{3}  - 3pqr \\  = (p + q + r)( {p}^{2}  +  {q}^{2}  +  {r}^{2}  - pq - pr - qr)

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