Question

p4s3 + 02= p4o10+so2
the mass of p4o10 produced if 440 gm of p4s3 is mixed with 384 gm of o2.

Answer 1

Moles of $P_4S_3 =  \frac {440 g} { 220.093 g/mol}$

= 1.999 moles;  

Moles of $O_2  = \frac {384 g} {32 g/mol}$

= 12 moles;

Balance equation:

$P_4S_3 + 8 O_2 = P_4O_{10} + 3 SO_2  ;$

Since 8 moles $O_2$ forms = 1 moles $P_4O_{10}$  

So, 12 moles of $O_2$ will form $= \frac {1} {8 } \times 12$

= 1.5 moles of $P_4O_{10} ;$

Mass of $P_4O_{10}  =  1.5 \times 283.886 g/mol$

= 425.829 g