Question

pa and pb are tangents to a circle from external point p . cd is another tangent touching the circle at q . if pa=12cm qc=qd= 3cm, then find pc+pd

Answer 1

Answer:

=18cm

Step-by-step explanation:

Tangent from an external point to a circle are equal,

∴ PA=PB -----eq (1)

∴ CA = CQ----eq(2)

∴DB=DQ--------eq(3)

Step-by-step explanation:

From the figure  we know that

PA=PC+AC

PA=PC+QC [∵ from eq(2) we know that QC=AC]

Substituting the given values, we get

12=PC+3

PC= 9cm

Similarly we can find PB

PB=PD+DB

PB=PD+QD

12=PD+3

PD=9cm

So PC+PD= 9+9=18cm

(answer)