पुढील समीकरण ax2+bx+C=0 या स्वरुपात लिहा P(3+6p)
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- Prime factorising 68600, we get, 68600
2×2×2×5×5×7×7×7
=2^3×5^2×7^3
- We know, a perfect cube has multiples of 3 as powers of prime factors. Here, number of 2's is 3, number of 5's is 2 and number of 7's is 3. So we need to multiply another 5 in the factorization to make 68600 a perfect cube. Hence, the smallest number by which 68600 must be multiplied to obtain a perfect cube is 5.
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