PA is a tangent to the circle with centre O.if BC=3cm,AC=4cm and triangle ABC congruent PAO then find OA and OP/AP
Answers
Answered by
5
Answer:
PO/PA = 5/4
In ΔBCA, ∠C = 90°
as tangent is perpendicular to radius so,
AB² = AC² + BC² = 3² + 4² ⇒ AB = 5
AB is diameter and O is center so,
OA = 5/2 = 2.5
As ΔACB is congruent to ΔPAO so,
AC / PA = BC / AO = AB/PO
4 /PA = 3/2.5 = 5/PO
PO/PA = 5/4
Solution of the question is attached below. Step wise explanation is given. If you have any problem or confusion, drop a comment. I will help you out throughly.
Hope this helps for you
Attachments:
Similar questions
Science,
7 months ago
English,
7 months ago
Accountancy,
7 months ago
Math,
1 year ago
Chemistry,
1 year ago