PA, PB are tangents to the circle with centre at 0. If Z APB = 36°, then
AOB=
Answers
Answered by
1
Answer:
90+90+36=216
360-216=144
Answered by
2
Answer:144°
Step-by-step explanation:
(ANGLE)AOB + (ANGLE) APB =180°
As (ANGLE) PAO & (ANGLE) PAB = 90°
SO by angle sum property in a quadrilateral
(ANGLE) AOB =180-36=144°
Similar questions