Math, asked by nishujha6800, 1 month ago

प्र
स. श्रे. के उन तीन पदों के मान ज्ञात कीजिए जिनका योग 12 तथा जिनके घनों का योग 408 है।
Find the three numbers in A. P. such that their sum is 12 and the sum of their cube​

Answers

Answered by poojalmehta12
0

Answer:

1,4,7 or 7,4,1

Step-by-step explanation:

Let the three numbers be a-d,a,a+d

GIVEN- sum is 12

so, a-d+a+a+d = 3a

3a=12

a=4

GIVEN- sum of cube is 408

so, (a-d)³ + (a)³ + (a+d)³=408

a³−d³−3a²d+3ad²+a³+a³+d³+3a²d+3ad²=408

3a³ +6ad² =408

a³+2ad²=136

4³ + 2(4)d² = 136

64 + 8d² = 136

8d² = 136-64

8d²=72

d²=9

d=±3

if a=4 and d=3, numbers will be 1,4,7

if a=4 and d= -3, numbers will be 7,4,1.

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