Question

प्र02 गॉस की प्रभेय लिखिये एवं सिद्ध कीजिये। 6/42
State and prove gausses theorem.​

Answer 1

Answer:

Gauss' theorem states that the surface integral of the electric field over a closed surface is equal to 1/ɛ₀ times the charge enclosed

Explanation:

Let the charge be = q

Let us construct the Gaussian sphere of radius = r

Now, Consider , A surface or area ds having having ds (vector)

Normal having the flux at ds:

Flux at ds:

d e = E (vector) d s (vector) cos θ

But , θ = 0

Therefore, Total flux:

C = f d Φ

E 4 π r2

Therefore,

σ = 1 / 4πɛo q / r2 × 4π r2

σ = q / ɛo