प्रश्न 3 यदि a: b = c: d हो तो K नियम द्वारा सिद्ध कीजिए कि a+c2 b2+d2 ac bd
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Given : a: b = c : d
To Find : k नियम द्वारा सिद्ध कीजिए
a²+c² : b²+d² = ac : bd
Solution:
a: b = c : d
=> a/b = c/d = k
=> a = bk and c = dk
a²+c² : b²+d² = ac : bd
LHS
= (a²+c²)/ (b²+d² )
= ( (bk)² + (dk)² )/ (b² + d²)
= k²(b² + d²)/(b² + d²)
= k²
RHS
= ac/bd
= bk.dk/bd
= bdk²/bd
= k²
LHS = RHS = k²
QED
Hence proved
a²+c² : b²+d² = ac : bd if a:b= c:d
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