PAB is secant of circle and PT is tangent then prove that PAxPT=PT^2 .... urgent plzz
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Given PAB is a secant intersecting the circle at A and B and PT is the tangent drawn from P.
Draw OL ⊥ AB and join points O, P; O, T; O, A.
PA x PB = OP2 – OA2
= OP2 – OT2 [OA = OT, radii]
Therefore, PA x PB = PT2 [Since OP2 – OT2 = PT2]
Draw OL ⊥ AB and join points O, P; O, T; O, A.
PA x PB = OP2 – OA2
= OP2 – OT2 [OA = OT, radii]
Therefore, PA x PB = PT2 [Since OP2 – OT2 = PT2]
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