Pace If Sec A = 5/4 and secB = 5√2/7, prove that A+B=45°
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0
Answer:
secA=
8
17
⇒cosA=
17
8
⇒sinA=±
17
15
cscB=
4
5
⇒sinB=
5
4
⇒cosB=±
5
3
Now cos(A+B)=cosAcosB−sinAsinB
⇒cos(A+B)=
17
8
.
4
5
−(±
17
15
.±
5
3
)=±
85
36
or ±
85
84
∴sec(A+B)=±
36
85
,±
84
85
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