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shall i answer this as per class 9 ?
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Answered by
16
Hi there !!
Given that ,
X travels from City A to B in Which
distance (s) = 540km
time(t) = 10 hrs
Speed of car X
speed= total distance/ total time
or
v = s/t
speed= 540km/10hrs
speed= 54km/hr
Also,
T travels from City B to C in which
distance (s) = 3200km
time(t) = 60 hrs
speed = distance/time
v = s/t
v = 3200km/60hrs
v = 53.333km/hr or 53.34km/hr
It can be seen that X has travelled with a speed of 54km/hr whereas Y has travelled with a speed of 53.34km/hr
Thus,
Car X has more speed
Given that ,
X travels from City A to B in Which
distance (s) = 540km
time(t) = 10 hrs
Speed of car X
speed= total distance/ total time
or
v = s/t
speed= 540km/10hrs
speed= 54km/hr
Also,
T travels from City B to C in which
distance (s) = 3200km
time(t) = 60 hrs
speed = distance/time
v = s/t
v = 3200km/60hrs
v = 53.333km/hr or 53.34km/hr
It can be seen that X has travelled with a speed of 54km/hr whereas Y has travelled with a speed of 53.34km/hr
Thus,
Car X has more speed
Answered by
6
Speed =
Speed of X =
Speed of Y =
Speed of Car X is more by 2/3 km per hour
Speed of X =
Speed of Y =
Speed of Car X is more by 2/3 km per hour
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