Question

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Question 1
Construct the right angled triangle ∆PQR, where ∠Q = 90°, QR = 8 cm and PR = 10 cm.

Answer 1

$\triangle PQR$ is the required triangle.

Step-by-step explanation:

Given,

Construct the right angled $\triangle PQR$ where $\angle Q=90\ degree$,$QR=8\ cm\ and\ PR=10\ cm$

Following steps:

• Draw a line segments $QR=8\ cm$ using scale.
• At $Q$, draw an angle $90\ degree$ using protector like $\angle RQX=90\ degree$
• Take $R$ as center and $10\ cm$ as radius, draw an arc $P$ on line $QX$  
• Join $PR$

Hence, $\triangle PQR$ is the required triangle.