Question

Page
5 cas traveling at 9 ms. -, accelerat
accelerates 4
the acceleration and the distance covered
in 50
,​

Answer 1

Explanation:

Initial Velocity of the car= 9m/s

Acceleration = 4m/s²

Time = 50 sec.

Final velocity of car = u+at = 9 + 4×50 = 209m/s

Distance = ut + 1/2a×t² = 9×50 + 1/2 × 4 × 50×50

= 450 + 5000 = 5400 m