Question

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Revision of lessons (ch-1)
23) Divide Rs. 1200 among A, B and C so that A gets twice and C thrice as much as B.
24. The cost of a house and its furniture is Rs. 78900 and the cost of the house is
chrice that of the furniture. Find the cost of the house.
23) Divide Rs. 270 among Ram, Hari and Jadu so that Hari may get half as much as
Ram and Jadu may get thrice as much as Hari.
26. Which is the greatest of the numbers of 5 digits that are multiples of 253?
27. Divide Rs. 335 among A, B and C so that B may get Rs. 10 more than A and C Rs.
15 more than B.
28. Of three boxes the first and second together contain Rs. 400, the second and the
Third Rs. 475 and the first and the third Rs. 625. Find the amount in each box.
29 In an examination a boy got altogether 95 marks in English and Mathematics, 105
arks in English and History and 80 marks in Mathematics and History. Find his marks
each subject.
30. How many times can the least number consisting of the digits 7,2,9,1 be subtracted
om the greatest number consisting of the same digits and what will be the last

31) Madhu has 25 mangoes less than the mangoes that Ram and Hari together have
Hari has thrice as many as Ram has. If there are altogether 95 mangoes, how many
each of them?​

Answer 1

Answer:

Hey mate☺

Step-by-step explanation:

Your answer no. 1:-

Total Rupees :- ₹1200

Suppose, Let B has:- ₹x

Hence, A would have:- ₹2x

And C would have :- ₹3x

Therefore, equation becomes:-

x+2x+3x= 1200

6x=1200

x=1200/6

x= 200

Hence, x i.e B has ₹200

Now, A= 2×200= ₹400

And C=3×200=₹600

We can say A has ₹400 B has ₹200 and Chas ₹600 , taking the total money asv₹1200.

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Your answer no.2:-

Total cost of both things together :- ₹78900

Let cost of furniture be :-₹x

Hence , cost of house :- ₹3x

Therefore, equation becomes:-

x+3x=78900

4x= 78900

x= 78900/4

x= 19725

Therefore, Furniture cost ₹19725

And house cost is 3×19725= ₹59175

___________________

Your answer no. 3:-

Total amount:-₹270

Let Ram has :- ₹x

Then ,Hari gets :-₹1/2(x)

And Jadu gets:-₹3(x/2)

Your equation becomes:-

x+x/2+3x/2=270

2x/2+3x/2+x/2=270

6x/2=270

6x=270×2

x=₹90

Therefore Ram has ₹90

Hari has ₹1/2(90) = ₹45

Jadu has 3×90/2= ₹135

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Your answer no.4:-

Greatest five digits number:- 99999

Dividing it with by 253

= 132 comes as remainder which means you need to subtract 132 from 99999

Therefore, your required number is:- 99999-132=99,867

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Your answer no.5:-

Total money:- ₹335

Let A has :- ₹x

Then, B will have:-₹10+x

And C will have:-₹15+(10+x)

Your equation becomes:-

x+(10+x)+(15+10+x)=335

3x+35=335

3x=335-35

x=300/3

x=100

Therefore, A has ₹100 B has ₹110 C has ₹125

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❤Hope it helps!❤

➡Mark brainliest please⬅