Question

PAGE NO.:
Three capacitars of equal capacitance 8pf connected in series.
find the equivalent capacitance of combination.​

Answer 1

Answer:

Equivalent capacitance = 2.66 pf

Explanation:

Equivalent capacitance in series =

                                        $\frac{1}{Ceq}=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}$

Given, C₁ = C₂ = C₃ = C =  8 pf

                $\frac{1}{Ceq} = \frac{1}{C}+\frac{1}{C}+\frac{1}{C}\\ \\\\=> \frac{1}{Ceq} = \frac{1}{8} + \frac{1}{8}+\frac{1}{8}$

         taking reciprocal,

                       $Ceq = \frac{8}{3}$

              ⇒ Ceq = 2.66 pf