Question

Paheli prepared a blue coloured solution of copper sulphate in beaker ‘A’ and placed an iron nail in it. Bittu prepared a yellowish green solution of Ferrous sulphate in beaker ‘B’ and placed a copper wire in it. What changes will they observe in the two beakers after an hour?

Answer 1

Answer:

The copper sulfate solution becomes ferrous sulfate and ferrous sulfate remains ferrous sulfate.

Explanation:

We must remember that Iron is more reactive element than copper hence CuSO4 + Fe= FeSO4 whereas FeSo4+Cu= FeSO4 + Cu. We also observe that heat is produced in the first experiment and no heat is produced in the second.