Question

pair of linear equation x-y=-1 and 3x+2y=12 any three sums​

Answer 1

Answer:

Given,

x−y+1=0....(1)

3x+2y−12=0....(2)

put x=0 in (1)

0−y+1=0⇒y=1

(0,1).....(a)

put y=0 in (2)

3x+2(0)−12=0→x=4

(4,0).....(b)

put x=0 in (2)

3(0)+2y−12=0→y=6

(0,6)......(c)

put y=0 in (1)

x−0+1=0⇒x=−1

(−1,0)...(d)

Answer 2

Answer:

hope it helps you........♥️♥️