Physics, asked by chawlaharman6611, 8 months ago

PARAGRAPH "A"
If the measurement errors in all the independent quantities are known, then it is possible to determine the error in
any dependent quantity. This is done by the use of series expansion and truncating the expansion at the first power
of the error. For example, consider the relation z = x/y. If the errors in x,y and z are Δx, Δy and Δz, respectively, then
z ± Δz = ((x ± Δx) / (y ± Δy)) = x/y (1 ± (Δx/x)) (y ± (Δy/y))⁻¹
The series expansion for (y ± (Δy/y))⁻¹ , to first power in Δy / y, is 1 ≠ (Δy / y). The relative errors in independent
variables are always added. So the error in z will be
Δz = z ((Δx/x) + (Δy/y))
The above derivation makes the assumption that Δ x/x ≪ 1, Δ y /y ≪1. Therefore, the higher powers of these
quantities are neglected.
In an experiment the initial number of radioactive nuclei is 3000. It is found that 1000 ± 40 nuclei decayed
in the first 1.0s. For |x| ≪ 1, ln(1 + x) = x up to first power in x . The error Δ????, in the determination of the
decay constant ????, in s⁻¹, is
(A) 0.04 (B) 0.03
(C) 0.02 (D) 0.01

Answers

Answered by addagirisai5955
1

Answer:

option (A)

Explanation:

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Answered by Anonymous
1

Sorry, I can't under stand....

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