Question

PARAGRAPH "A"
If the measurement errors in all the independent quantities are known, then it is possible to determine the error in
any dependent quantity. This is done by the use of series expansion and truncating the expansion at the first power
of the error. For example, consider the relation z = x/y. If the errors in x,y and z are Δx, Δy and Δz, respectively, then
z ± Δz = ((x ± Δx) / (y ± Δy)) = x/y (1 ± (Δx/x)) (y ± (Δy/y))⁻¹
The series expansion for (y ± (Δy/y))⁻¹ , to first power in Δy / y, is 1 ≠ (Δy / y). The relative errors in independent
variables are always added. So the error in z will be
Δz = z ((Δx/x) + (Δy/y))
The above derivation makes the assumption that Δ x/x ≪ 1, Δ y /y ≪1. Therefore, the higher powers of these
quantities are neglected.

Consider the ratio r = (1-a) / (1+a) to be determined by measuring a dimensionless quantity a. If the error in the
measurement of a is Δa ( Δ a /a ≪ 1 ) , then what is the error Δr in determining r ?
(A) Δa / (1+a)² (B) 2Δa / (1+a)² (C) 2Δa / (1-a²) (C) 2aΔa / (1-a²)

Answer 1

measurement of a is Δa ( Δ a /a ≪ 1 ) ,

Δ x/x ≪ 1, Δ y /y ≪1.

Answer 2

Answer:

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Explanation:

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