Question

Parallel lines are cut by a transversal such that the alternate interior angles have measures of 3x + 17 and x + 53 degrees.
Find the value of x.

Answer 1

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(NOTE: ALTERNATE ANGLES ARE ALWAYS EQUAL IF THE LINES ARE PARALLEL)

$3x + 17 = x + 53 \\ = ) \: \: 3x - x = 53 - 17 \\ = ) \: \: 2x = 36 \\ = ) \: \: x = \frac{36}{2} \\ = ) \: x = 18 \: degrees$

THEREFORE VALUE OF X= 18 DEGREES.

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