Question

parameter of of a rectangular field is 64 cm and one of the side is 8 cm calculate its area​

Answer 1

Answer:

area of the rectangular field is 256cm²

Step-by-step explanation:

given that :

perimeter of a rectangular field is 64 cm

one side is 8cm

let that side be length of the given rectangular field L = 8cm

we know that formula for perimeter of a rectangle is 2(L + B)

B = breadth of rectangle.

so, 2( L + B ) = 64 cm

(L + B) = 64/2

(L + B) = 32;

substitute value of L in above formula

( 8 + B ) = 32

B = 32 - 8

B = 24cm

length = 8cm , breadth = 32 cm

area of a rectangle = (length) ( breadth)

area = (L)(B)

= (8)(32)cm²

= 256cm²

area of the rectangular field is 256cm²

Answer 2

Answer:

here,

1st lets find length,

perimeter of rectangular field= 64

now, let breadth = 8cm

and length= l

now,

perimeter of rectangle= 2(l+b)

or 64= 2( l+8)

or l= p/2- 8

or, l= 64/2-8

or, l= 32-8= 24

therefore, length= 24cm

now area,

here,

formula to calculate area of a rectangle= lengthxbreadth

or area= 24cmx8cm= 192cm square

therefore, area of the rectangular field= 192 cm square.

Step-by-step explanation: