Question

Parashant has a cardboard of a Length 120 cm and breadth 80 cm He cut it into 4 equal rectangles S,T, U V as shown below
Perimeter?
Area? Area of S+T+U +V= ?
a) is the Perimeter of A is equal to the perimeter of S+ T+U+V? Give a reason for your answer
b) Is the area of A= Area of S+ T+U +V? Give a reason for your answer
Step by step

Answer 1

Answer:

The perimeter of big cardboard is 2(l + b)

= 2×120 + 2×80

= 400 cm

Area of big cardboard is l× b

= 120 ×80

= 9600 cm²

Area of rectangle A = Area of S + T+ U+ V

because S,T,U,V are cut from cardboard A

They are cut in equal part so ..

Area of S = T=U=V which is 9600 ÷ 4

= 2800 cm²

Perimeter of S=T=U=V =2×60 +2×40

= 200 cm

S,T,U,V IS A PART OF RECTANGLE A SO THEIR AREA AND PERIMETER IS EQUAL

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