Parashant has a cardboard of a Length 120 cm and breadth 80 cm He cut it into 4 equal rectangles S,T, U V as shown below
Perimeter?
Area? Area of S+T+U +V= ?
a) is the Perimeter of A is equal to the perimeter of S+ T+U+V? Give a reason for your answer
b) Is the area of A= Area of S+ T+U +V? Give a reason for your answer
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Answer:
The perimeter of big cardboard is 2(l + b)
= 2×120 + 2×80
= 400 cm
Area of big cardboard is l× b
= 120 ×80
= 9600 cm²
Area of rectangle A = Area of S + T+ U+ V
because S,T,U,V are cut from cardboard A
They are cut in equal part so ..
Area of S = T=U=V which is 9600 ÷ 4
= 2800 cm²
Perimeter of S=T=U=V =2×60 +2×40
= 200 cm
S,T,U,V IS A PART OF RECTANGLE A SO THEIR AREA AND PERIMETER IS EQUAL
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