Parikh is starting a new batch, named go for gold, where he will be preparing students for acm-icpc. He has selectively chosen 9 students from delhi region. He took a test. The ranks of the students in the test were made their roll numbers. Now, each student has a distinct number from 1 to 9. He now wants to choose 6 students, in the strictly increasing order of their ranks. What is the number of such combinations.
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Answer:
84
Step-by-step explanation:
C[9,6)=9!/(6!*3!)=84
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