Math, asked by valikeabhiramyadav, 5 months ago

PARK CLEANING:- Inspired by the “Swachh Bharat mission”, Priya and her friends Sunita, Kavya and Hema decided to clean their society park. Her friends clean 2/5, 1/3 and 1/4 part of the park respectively. Using this data answer the following questions 19 & 20.How much part of the park will be left for Priya to clean? *
2 points
( a ) 1/60
( b ) 29/60
( c ) 10/20
( d ) none of these
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Answers

Answered by 123AkshayVarma123
2

Answer:

(d) none of these

Step-by-step explanation:

First, we have to convert 2/5, 1/3 and 1/4 into like fractions.

So, we take the L.C.M of 5, 3 and 4 which is 60.

So, we can write 2/5, 1/3 and 1/4 as 12/60, 20/60 and 15/60 respectively.

12/60 + 20/60 + 15/60 = (12 + 20 + 15)/60

                                     = 47/60

If we subtract 47/60 from the whole park we get

1 - 47/60 = 1/1 - 47/60

               = 60/60 - 47 /60

               = 3/60

               = 1/20

As there is no option which says  3/60 or 1/20, (d) is the correct opion

Please make me brainliest.

Answered by amitnrw
4

Given : Inspired by the “Swachh Bharat mission”, Priya and her friends Sunita, Kavya and Hema decided to clean their society park. Her friends clean 2/5, 1/3 and 1/4 part of the park respectively

To Find :  How much part of the park will be left for Priya to clean? *

( a ) 1/60

( b ) 29/60

( c ) 10/20

( d ) none of these

Solution:

 Sunita = 2/5

 Kavya = 1/3

  Hema = 1/4

 Rest  = Priya

 Let say total work  = 60x

 Sunita = (2/5)60x  = 24x

 Kavya = (1/3) 60x  = 20x

  Hema = (1/4)60x  = 15x

  Priya = 60x - (24x + 20x + 15x)  =  x

part of the park will be left for Priya  = x/60x  = 1/60

option a) is correct

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