Question

part 4 .......solve clearly

Answer 1

(x^3 +1/x^3)(x^3-1/x^3)(x^6+1/x^6)
(a+b)(a-b)= (a^2- b^2)
(x^6-1/x^6)(x^6+1/x^6)
(x^6)^2 (1/x^6)^2
x^12-1/x^12

Answer 2

Answer:

$x^{12}$ - $\frac{1}{x^{12} }$

Step-by-step explanation:

(x³ - $\frac{1}{x^3}$) (x³ + $\frac{1}{x^3}$) (x^6  + $\frac{1}{x^6}$)

⇒ by using:  a² - b² = (a+b)(a-b)

⇒(x³)² - ($\frac{1}{x^3}$)² (x^6 + $\frac{1}{x^6}$)

⇒(x^6 - $\frac{1}{x^6}$) (x^6 + $\frac{1}{x^6}$)    {(a²)³ = $a^{2*3}$}

⇒ Using a² - b²=  (a+b)(a-b):

⇒ ($x^{6}$)² - ($\frac{1}{x^6}$)²

⇒ $x^{12}$ - $\frac{1}{x^{12} }$

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Hope This Helps!

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