Question

PART A (Secton-2)
17.
Once 4 students Rahul, Arun, Ajay & Vijay went for picnic at hill station. They decided
to make a conical tent at park. They were carrying 300 m sq. cloth with them. The
height of the tent is 10 meter & diameter is 14 meter. They used the remaining cloth fo
the floor
D
How much cloth was used for the floor?
a- 31.6 sq. m
b- 16 sq. m
C- 10 sq. m
d- 20 sq. m
11)
What was the volume of tent?
a- 300 m cube.
b- 160m cube.
C- 513.3 m cube.
d- 500 m cube
III)
What was the area of floor?
a- 50 sq. m
b-100 sq. m
C- 150 sq. m
d-154 sq. m
IV)
What was the total surface area of tent?
a- 400 sq. m
b- 422.4sq. m
C- 300sq. m
d-400sq. m​

Answer 1

Answer:

31.sq.m

Step-by-step explanation:

curved surface area of the cone= pi rl

the area of the cloth the 4 friends were carrying with them= 300 m.sq.

the height of the conical tent= 10 m

the diameter of the conical tent= 14 m

so the radius of the conical tent. r=14/2= 7 cm

the slant height 'l' of the conical tent is,√h²+r² = √10²+7²=√149=12.2 m

thus, the required area of the cloth for making the tent is= curved surface area of conical tent= $\pi$rl = 22/7 multiply by 7 multiply 12.2= 268.4 m²

now, the remaining area of the cloth used for the floor is = 300 m²- 268.4 m²= 31.6 m².

2nd)) 513.3 m sq.

Answer 2

Given : 300 sq.m cloth used to make tent ,.

conical tent with height 10m and diameter 14m.

The remaining cloth was used for the floor​

To find :

 What is the slant height of the tent?

   What was the volume of the tent?

 What was the area of the floor?

Solution:

area of the floor = π7²

= (22/7) (7)²

= 154   m²

conical tent with height 10m and diameter 14m.

=> radius = 14/2 = 7 m

h = 10 m

Formula for slant Height = √r² + h²

slant height L = √7² +10² = √149 m

= 12.2 m

 

Curved surface Area = πRL

=(22/7) ( 7)12.2

= 268.4  m²

Cloth used for floor = 300 -  268.4 = 31.6 m²

Total Surface area =  300 Sq m as that much cloth was available

 

volume of the tent = (1/3)πR²h

= (1/3)(22/7)*7²*10

=  513.3 m³

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