part carries 1 mark.
17) Once four friends Rahul, Arun, Ajay and Vijay went for a picnic at a hill station. Due to peak
season, they did not get a proper hotel in the city. The weather was fine so they decided to make a
conical tent at a park. They were carrying 300m2 cloth with them. As shown in the figure they
made the tent with height 10m and diameter 14m. the remaining cloth was used for the floor
Answers
Given : 300 sq.m cloth used to make tent ,.
conical tent with height 10m and diameter 14m.
The remaining cloth was used for the floor
To find :
What is the slant height of the tent?
What was the volume of the tent?
What was the area of the floor?
Solution:
area of the floor = π7²
= (22/7) (7)²
= 154 m²
conical tent with height 10m and diameter 14m.
=> radius = 14/2 = 7 m
h = 10 m
Formula for slant Height = √r² + h²
slant height L = √7² +10² = √149 m
= 12.2 m
Curved surface Area = πRL
=(22/7) ( 7)12.2
= 268.4 m²
volume of the tent = (1/3)πR²h
= (1/3)(22/7)*7²*10
= 513.3 m³
Learn More
Mr. David and his class of 110 students went for a camping trip. He ...
brainly.in/question/16014974
brainly.in/question/11763695
Given :
- cloth used to make tent = 300 m².
- Height of conical tent = 10m and
- Diameter of conical tent = 14m.
- The remaining cloth was used for the floor .
To find :
(i) How much cloth was used for the floor ?
(a) 31.6m² (b)16m² (c) 10m² (d)20m²
(ii) What was the volume of the tent ?
(a)300m³ (b)160m³ (c)513.3m³ (d)500m³
(iii)What was the area of the floor ?
(a)50m² (b)100m² (c)150m² (d)154m²
(iv)What was the T.S.A of the tent ?
(a)400m² (b)422.4m² (c)300m² (d)400m²
(v) What was the slant height of the tent ?
(a)12m (b)12.2 m (c)15 m (d)17 m
Solution :-
we know that,
- Radius = (Diameter/2) .
- Slant height = [Radius² + Height²]
- CSA of cone = π * radius * slant height .
- Base area of cone = π * (radius)² .
- TSA of cone = CSA + Base Area.
- Volume of cone = (1/3) * π * (radius)² * height .
Answer (iii) :-
→ Area of the floor = (14/2) = 7 m.
→ Cloth used for floor = Base Area of conical tent = π * (radius)² = (22/7) * 7 * 7 = 154 m² (d) (Ans.)
Answer (v) :-
→ Slant height of tent = √(r² + h²) = √(7² + 10²) = √(49 + 100) = √(149) ≈ 12.2 m (b) (Ans.)
Answer (i) :-
→ cloth was used for the floor = Total cloth - CSA of conical tent = 300 - {(22/7) * 7 * 12.2} = 300 - 268.4 = 31.6 m² (a) (Ans.)
Answer (iv) :-
→ T.S.A of the tent = CSA + Base Area = 268.4 + 154 = 422.4 m². (b) (Ans.)
Answer (ii) :-
→ Volume of the tent = (1/3) * (22/7) * (7 * 7) * 10 = (1540/3) ≈ 513.3 m³ (c) (Ans.)
Learn more :-
from a solid cylinder whose height is 3.6 cm and diameter 2.1 CM a conical cavity of the same height and the same diamet...
https://brainly.in/question/24336372
A hemisphere of radius 21 cm is completely filled with milk. There is a hole in
the bottom whose radius is 0.1 cm. If ra...
https://brainly.in/question/25349591