Question

part of racing track is to be desinged for a curvature of 72m.we are not recommending the vehicle to drive faster than 216kmph with what angle should the road be tilled?​

Answer 1

Answer:

tan theta= (Vmax)^2/rg

Vmax=216kmph

r= 72 m

g= 9.8

Answer 2

Answer:

Ө =  tan inverse( 5 )

 Ө = 78.69 degree

Explanation:

Given data :-  

radius of curvature r = 72m

vmax = 216 km/hr = 216 x (5/18 ) = 60 m/s

What we have to find out :-

 1) angle should the road be tilted i.e angle of banking = Ө= ?

Solution :-

1)The angle of banking is given by,  

 

Ө =  tan inverse ( v square / rg )

   =  (   / 72 x10 )              g = 10 m/  

    =  (3600 /720 )

 Ө =  ( 5 )

 Ө = 78.69 degree  

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Explanation: