Question

partial fractions. pls answer my question. don't spam.​

Answer 1

Answer:

$\frac{3x + 4}{ {x }^{2} - 3x + 2 } \\ = \frac{3x + 4 }{ {x}^{2} - 2x - x + 2 } \\ = \frac{3x + 4}{ x(x - 2) - 1(x - 2)} \\ = \frac{3x + 4}{( x - 2)(x - 1)}$

$\frac{3x}{x - 2} - (\frac{ - 4}{x - 1} )$

$\frac{a}{x - 2} = \frac{3x}{x - 2} \\ = > a = 3x$