partical moves in straight line with contant retardation 10m/s2 for 3second. if it starts with 10m/s towards right then determine its displacement
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Explanation:
Given,
u=10m/s
a=−2m/s
2
n=5
The distance covered by the particle in n
th
second is
S
n
=u+
2
a
(2n−1)
S
5
=10−
2
2
(2×5−1)
S
5
=10−9=1m
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