Question

Particle 'A' has a velocity of VA=8m/s
along positive Xaxis.Particle B has a
velocity VB= ( 4i+4Underoot3j ;) m/s

Find the magnitude of the relative velocity of B with respect to A​

Answer 1

Answer:

8 m/s

Explanation:

Relative velocity of B wrt A VBA = VB–VA

velocity of A = 8i^

VBA = 4i^ + 4 unroot 3j^ – 8i^

= –4i^ + 4 unroot 3 j^

magnitude = unroot( 4²+ (4 unroot 3)²)

= 8 m/s