Question

particle A is moving with velocity (6i^+10j^)m/s and particle B is moving with (3i^+6j^)m/s magnitude of velocity ofAw.r.t B is​

Answer 1

Answer:

Particle A is moving with velocity 6i 10j

particle A is moving with velocity (6i^+10j^)m/s and particle B is moving with (3i^+6j^)m/s magnitude of velocity ofAw.

Answer 2

Answer:

5 m/s

Explanation:

v1 - v2 = $\\(6i+10j)-(3i+6j)$

v1-v2 = $(6i-3i) + (10j-6j)$

v1-v2= $3i+4j$ m/s

magnitude of velocity of A w.r.t B = $\sqrt(3^{2})+(4^{2})$

= $\sqrt25$

= 5 m/s