Question

Particle is moving with a constant speed in a circle of radius . What is the magnitude of average acceleration after half revolution?

Answer 1

Let the particle start from A. And end its journey at B.

Since the position of the particle at the initial and final point is diametrically opposite, the velocity vector at B reverses.

Given:-

Initial velocity = 5 m/s

Final velocity = -5 m/s (here, the minus sign indicates its opposite direction.)

Distance covered = πr = 5π meter

We know that,

Speed = Distance / Time

=> Time = Distance / Speed

=> Time = 5π / 5 = π seconds

So, total time taken = π seconds

AverageAcceleration=(finalvelocity)−(initialvelocity)/totaltimetaken

= 5−(−5)/π m/s2

=10/π m/s2

Therefore, the average acceleration of the particle is 10/π m/s2