Question

particle starts from rest and traverses a distance I with uniform acceleration, then moves uniformly over a further distance 21 and finally comes to rest after moving a further distance 31 under uniform.retardation. Assuming entire motion to be rectilinear motion, the ratio of average speed over the journey to the maximum speed on its way is​

Answer 1

Answer:

$\frac{3}{5}$

Explanation:

AB=L,BC=2L,CD=3L

It starts from rest and accelerates and then remains in uniform velocity and then retards, this means the maximum velocity will be at point B and let it be v

The area under velocity time graph is displacement and hence we have three equations corresponding to regions AB,BC and CD

2vt1=2,vt2=2L,vt3=3L

t1+t2+t3=+v2L+v2L+v6L=v10L

and the average velocity

=totaltimetotaldisplacement

vˉ=t1+t2+t36L=53v

Hence, vvˉ=53