Question

paul and jason started a journey of 110km .If david takes 22 minutes more than jason who is travelling at 60kmph calculate the speed of david
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Answer 1

We are given, Distance covered d = 360 km . Speed of sa = 40 km/h . Speed of Paul = 60 km/h . Time taken by Lisa = Distance / Speed of Lisa . =360/40 . =9 hours. Time taken by Paul = D Distance / Speed of Paul. =360/60 . =6 hours. 9 > 6 . Therefore, Paul will reach the destination 3 hours earlier i.e. 3*60=180 minutes earlier.