Math, asked by goswshu, 6 months ago

Paul has twice as many Pokemon as Peter. Peter has three times as many Pokemon as Edward. If altogether they have 70 Pokemon, how many Pokemon does Peter have?

Answers

Answered by ZunaidKhan29
2

Answer:

Peter have 21 pokemon.

Step-by-step explanation:

Let the number of Edward's Pokemon be x

Edward's Pokemon=x

Peter's Pokemon=3x

Paul's Pokemon=3x×2=6x

(3x×2)+3x+x=70

6x+4x=70

10x=70

x=70/10

=7

Peter's Pokemon is 3x=3×7

=21

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Answered by pjgaikar06
0

Answer:

Peter have 21 pokemon.

Step-by-step explanation:

Let the number of Edward's Pokemon be x

Edward's Pokemon=x

Peter's Pokemon=3x

Paul's Pokemon=3x×2=6x

(3x×2)+3x+x=70

6x+4x=70

10x=70

x=70/10

=7

Peter's Pokemon is 3x=3×7

=21

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