Math, asked by chana7SH6ASHAsisumar, 1 year ago

Pawan is now half of his father's age.Twenty years ago,the age of father was six times of son's age.Find the age of father and son ...............PLz help ...i wl giv u smethng..

Answers

Answered by mysticd
11
let at present
father age = x years
pawan age =x/2 years

20 years ago,
father age=(x-20)
pawan agw age=(x/2-20)
given
20 years ago age of father was 6 times of son's age
x-20=6(x/2-20)

x-20=6*x/2- 6*20
x-20=3x-120
120-20=3x-x
100=2x
2x=100
x=100/2
x=50
therefore
at present
father age=x=50 years
pawan age =x/2=50/2=25 years
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