Math, asked by lilamukherjeecoco, 10 months ago

payal can do a work in 12 days and parul can do the work in 20 days. they worked together for three days and then payal left.in how many days will parul finish the remaining work​

Answers

Answered by ninjasplayhouse
6

Answer:

let payal be a

and parul be b

efficiency of A = 1/ 12

efficiency of B = 1/20

Work done for last 12 days by B = 12/20 {(12*1/20)}

Remaining work = 1 - 12/20

= 8/20

Together efficiency of A & B = 1/12 +1/20 = 2/15

8/20 whole divided by 2/ 15

which is = 8/20*15/2 = 3 days

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Answered by achintyafouzder1976
2

Answer:

5 days

Step-by-step explanation:

12:20::3:x

12/20 = 3/x

3/5 = 3/x

therefore, x = 5

ans) Parul will finish the work in 5 days

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