pb3 o4 gives rise to pbo + O2 balance this equation
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2pb3O4–6PbO + O2
Put 2 in front of the pb3o4 so the number lead becomes 3 times 2 i.e 6 and then you have to put 6 in front of lead oxide so the number of lead atoms are balanced in both sides now see the oxygen, it's 4 times 2 on the reactant side and same on the product side so it is chemically balanced.
BEesha:
Thank you for your answer and response
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