pcl5 =pcl3 +cl2 the number of moles of cl2 produce will be ? if one mol of pcl5 is heated at 250 degree Celsius in a vessel of capacity of 10 dm^3 at 250 degrees Celsius kc =0.041
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PCl
5
dissociates according to
PCl
5
→PCl
3
+Cl
2
Initial conc. : a(let) 0 0
Final conc : a(1-x) ax ax
where x is the degree of dissociation
[Cl
2
] = 0.1 = ax ….......(i)
k
c
=([PCl
3
][Cl
2
])/[PCl
5
]
= (ax. ax)/a(1-x) = 0.0414
= ax
2
/(1-x) = 0.0414
= ax
2
=0.0414 { 1-x=1 , since x
= 0.1 x = 0.0414 { From (i) }
= x=0.414
From (i) ,
a = 0.1/0.414 = 0.2415
So, moles of PCl
5
added =0.2415 moles.
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