Chemistry, asked by rk2829048, 6 months ago

pcl5 =pcl3 +cl2 the number of moles of cl2 produce will be ? if one mol of pcl5 is heated at 250 degree Celsius in a vessel of capacity of 10 dm^3 at 250 degrees Celsius kc =0.041​

Answers

Answered by prathameshvedant
0

Answer:

ANSWER

PCl

5

dissociates according to

PCl

5

→PCl

3

+Cl

2

Initial conc. : a(let) 0 0

Final conc : a(1-x) ax ax

where x is the degree of dissociation

[Cl

2

] = 0.1 = ax ….......(i)

k

c

=([PCl

3

][Cl

2

])/[PCl

5

]

= (ax. ax)/a(1-x) = 0.0414

= ax

2

/(1-x) = 0.0414

= ax

2

=0.0414 { 1-x=1 , since x

= 0.1 x = 0.0414 { From (i) }

= x=0.414

From (i) ,

a = 0.1/0.414 = 0.2415

So, moles of PCl

5

added =0.2415 moles.

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