PD p(x) x-1 is a factor of x^3-1
Answers
Answered by
0
Answer:
yes
Step-by-step explanation:
because
g(x)=x^3-1
g(1)=1^3-1=1-1=0
g(1)=0
where 1 is the zero of p(x)
Answered by
0
Answer:
g(x) is a factor of p(x)
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