Question

pen-
B
47. A pendulum of length 28 cm oscillates such that its
string makes an angle of 30° from the vertical when it is at 1 corner of extreme positions find the ratio of the distance to displacement of the Bob of the pendulum when it moves from one extreme positions to the other.​

Answer 1

Answer:

your answer is here

Explanation:

Angle made with vertical at extreme position=30°

When it goes from one extreme position to the other extreme position, angle traversed =2×30=60°

Radius =28cm

Distance travelled =

360

60

×2Πr=

6

176

cm

Displacement =2×rsin30=2×28×

2

1

=28cm

Distance to displacement ratio =

(6×28)

176

=22:21

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Answer 2

Answer:

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Angle made with vertical at extreme position= 30°

When it goes from one extreme position to the other extreme position, angle traversed = 2×30=60°

Radius = 28cm

Distance travelled = (60/360) × 2πr = 176/6 cm

Displacement = 2× r sin 30° = 2×28×1/2 = 28 cm

Distance to displacement ratio = 176/(6×28) = 22:21

Ratio is 22:21.

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