Question

percentage consists of an organic compound found in senti 39.9 percent carbon 6.7% hydrogen and the rest of his oxygen its molecular mass of a compound is 60 determine the molecular formula of the compound​

Answer 1

Answer:

m. mass*39.9/6.7*1000

Answer 2

The molecular formula is $C_2H_4O_2$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C= 39.9 g

Mass of H = 6.7 g

Mass of O = 100-(39.9+6.7)g = 53.4 g

Step 1 : convert given masses into moles.

Moles of C =$\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{39.9g}{12g/mole}=3.3moles$

Moles of H =$\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.7g}{1g/mole}=6.7moles$

Moles of O =$\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.4g}{16g/mole}=3.3moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{3.3}{3.3}=1$

For H = $\frac{6.7}{3.3}=2$

For O =$\frac{3.3}{3.3}=1$

The ratio of C : H: O= 1: 2: 1

Hence the empirical formula is $CH_2O$

The empirical weight of $CH_2O$ = 1(12)+2(1)+1(16)= 30g.

The molecular weight = 60 g/mole

Now we have to calculate the molecular formula:

$n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{60}{30}=2$

The molecular formula will be=$2\times CH_2O=C_2H_4O_2$

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