Percentage error in measurement of mass and radius of a solid sphere are 0.5% and 0.3% respectively. What is percentage error in the measurement of its density?
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Answer:
Moment of inertia of solid sphere is given by I = 2/5MR²
Where I is moment of inertia
M is the mass of sphere
R is the raidus of sphere.
For finding error in inertia , formula will be
∆I/I = 2∆R/R + ∆M/M
∆/l × 100 = 2{∆R/R × 100} + ∆M/M × 100
% in inertia = 2 × % in radius + % in mass
= 2 × 2 % + 1 %
= 5 %
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Answered by
0
Answer:
Moment of inertia of solid sphere is given by I = 2/5MR²
Where I is moment of inertia
M is the mass of sphere
R is the raidus of sphere.
For finding error in inertia , formula will be
∆I/I = 2∆R/R + ∆M/M
∆/l × 100 = 2{∆R/R × 100} + ∆M/M × 100
% in inertia = 2 × % in radius + % in mass
= 2 × 2 % + 1 %
= 5 %
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