Chemistry, asked by wecwc1569, 10 months ago

percentage marks of each elements present in the following compound of sodium sulphate..

Answers

Answered by swapnaritam

0

Na2SO4=(23×2)+32+(16×4)
=46+32+64
=142 a.m.u.

Na=(46/142)×100
=32.39%

S=(32/142)×100
=22.53%

O=(64/142)×100
=45.07%

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