Question

Percentage of cation in ammonium dichromate

Answer 1

To find the percentage of ammonium cations in ammonium dichromate
Divide the total mass of the ammonium cations by the molar mass of ammonium dichromate and multiply times 100

%NH4+ = 36.078g/mol÷ 252.07g/mol×100= 14.313%

Answer 2

Given that,

The ammonium dichromate is

$(NH_{4})_{2}Cr_{2}O_{7}$

The molar mass of ammonium dichromate is 252.07 g/mol.

We know that,

The molar mass of ammonium cation $(NH_{4})^{+}$ is 18.039 g/mol.

There are two moles of ammonium cations in one mole of ammonium dichromate.

We need to calculate the molar mass of $(NH_{4})_{2}$

Using formula of molar mass

$molar\ mass =2\times18.039$

$molar\ mass =36.078\ g/mol$

We need to calculate the percentage of cation in ammonium dichromate

Using formula of percentage

$\text{Percentage of ammonium cations }=\dfrac{\text{molar mass of ammonium cations }}{\text{molar mass of ammonium dichromate}}\times100$

Put the value into the formula

$\text{Percentage of ammonium cations }=\dfrac{36.078}{252.07}\times100$

$\text{Percentage of ammonium cations }=14.3\%$

Hence, The percentage of cation in ammonium dichromate is 14.3 %