Percentage of nitrogen in urea will be
(1) 23.3%
(2) 46.6%
(3) 35.9%
(4) 53.4%
how to calculate
with steps
Answers
Answered by
4
urea=> NH2-CO-NH2
total mass=60
mass of nitrogen = 14, 2 molecules hence m=28
N%= mass of nitrogen X 100
mass of urea
= 28 X 100
60
N%= 46.6%
total mass=60
mass of nitrogen = 14, 2 molecules hence m=28
N%= mass of nitrogen X 100
mass of urea
= 28 X 100
60
N%= 46.6%
Answered by
5
Hlo mate your solution
Urea has the formula NH2-CO-NH2 ,
i.e. C H 4N2O
Mol wt = 60 g/mol
Atomic mass of N = 14 & no of atoms = 2 i.e. 28 g/mol of urea
Thus the % = 28/60 x 100 = 46.66 %
Urea has the formula NH2-CO-NH2 ,
i.e. C H 4N2O
Mol wt = 60 g/mol
Atomic mass of N = 14 & no of atoms = 2 i.e. 28 g/mol of urea
Thus the % = 28/60 x 100 = 46.66 %
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