Question

Percentage of Se in peroxidase anhydrase enzyme is 0.5% by
weight (at. wt. of Se = 78.4) then minimum molecular weight
of peroxidase anhydrase enzyme is
(a) 1.568 × 10³ (b) 15.68
(c) 2.136 × 10⁴ (d) 1.568 × 10⁴

Answer 1

Minimum molecular weight  of peroxidase anhydrase enzyme is 1.568 × 10⁴

Explanation:

From the given data, it can be known that

Percentage of Se in peroxidase anhydrase enzyme = 0.5% by

weight.

That is 0.5 g of Se present in 100 g peroxidase anhydrase enzyme

Then 78.4 g of Se must be present in enzyme =$\frac{78.4\times100}{0.5} =1.568\times 10^{4}$

Therefore, minimum molecular weight  of peroxidase anhydrase enzyme is 1.568 × 10⁴g