percentage problem???
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Let the larger number be a
And smaller number be b
According to first condition,
80% of b + 4 = 40% of a
=> 80b/100 +4 = 40a/100
=> 40a/100 - 80b/100= 4
=> 2a/5 - 4b/5 = 4
=> ( 2a - 4b)/5 = 4
=> 2a - 4b = 20
=> a - 2b = 10 --------(1)
According to second condition,
a = b + 125
=> a - b = 125 ------(2)
On subtracting equation 1 from 2, we get
(a - b) - (a-2b) = 125 - 10
=> a - b - a + 2b = 115
=> b = 115
Smaller number = 115
Now,
On substituting the value of b in equation (2), we get
a - 115 = 125
=> a = 125 +115
=> a = 240
Larger number = 240
And smaller number be b
According to first condition,
80% of b + 4 = 40% of a
=> 80b/100 +4 = 40a/100
=> 40a/100 - 80b/100= 4
=> 2a/5 - 4b/5 = 4
=> ( 2a - 4b)/5 = 4
=> 2a - 4b = 20
=> a - 2b = 10 --------(1)
According to second condition,
a = b + 125
=> a - b = 125 ------(2)
On subtracting equation 1 from 2, we get
(a - b) - (a-2b) = 125 - 10
=> a - b - a + 2b = 115
=> b = 115
Smaller number = 115
Now,
On substituting the value of b in equation (2), we get
a - 115 = 125
=> a = 125 +115
=> a = 240
Larger number = 240
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